show that the range of the first seven multiples of the smallest odd prime number is also a multiple of that prime number
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Answered by
22
hey mate
here is your answer
the smallest odd prime number is 3
the first 7 multiples of 3=3,6,12,18,15,18,21
the range of this multiples=highest number-smallest number
=21-3
=18
and 18 is divisible by 3. (so proved)
here is your answer
the smallest odd prime number is 3
the first 7 multiples of 3=3,6,12,18,15,18,21
the range of this multiples=highest number-smallest number
=21-3
=18
and 18 is divisible by 3. (so proved)
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Answered by
1
Answer:
The range of the first seven multiples of the smallest odd prime number is 18.
To find:
Show that the range of the first seven multiples of the smallest odd prime number is also a multiple of that prime number
Solution:
The smallest odd prime number is 3
7 multiples of 3 are 3, 6, 9, 12, 15, 18, 21
Range of the data = largest – smallest
= 21 – 3 = 18
18 is also a multiple of 3.
Result:
The range of the first seven multiples of the smallest odd prime number is 18.
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