show that the rate of change of momentum is equal to product of mass and acceleration
Answers
Answered by
34
relation between Force and momentum
pi= mass x initial velocity
= mu
pf=mass x final velocity
= MV
∆P= pf -pi
=mv-mu
=m(v-u). (1)
=mass x change in velocity
also, F is directly proportional to pf-pi/t
or F=k(pf-pi/t) where k is constant of proportionality
using (1)
F= m(v-u)/t
= m x (v-u/t)
= m x a. as v-u/t=a
thus we can say Change in momentum will directly effect the force.
pi= mass x initial velocity
= mu
pf=mass x final velocity
= MV
∆P= pf -pi
=mv-mu
=m(v-u). (1)
=mass x change in velocity
also, F is directly proportional to pf-pi/t
or F=k(pf-pi/t) where k is constant of proportionality
using (1)
F= m(v-u)/t
= m x (v-u/t)
= m x a. as v-u/t=a
thus we can say Change in momentum will directly effect the force.
Answered by
37
Hey user..
We have to show that F=ma
We know that rate of change of momentum is directly proportional to the force applied nd in direction of force
Rate of change of momentum is directly proportional to MV1 - MV2/t
F is directly proportional to M(V1 -V2)/t
F is directly proportional to Ma.
F=kma(k is constant of proportionality)
nd k=1.
F=ma
Hope this will help u.
We have to show that F=ma
We know that rate of change of momentum is directly proportional to the force applied nd in direction of force
Rate of change of momentum is directly proportional to MV1 - MV2/t
F is directly proportional to M(V1 -V2)/t
F is directly proportional to Ma.
F=kma(k is constant of proportionality)
nd k=1.
F=ma
Hope this will help u.
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