show that the ratio r of one root of the equation ax²+bx+c=0, to the other given by equation acr²+(2ac-b²)r+ac=0
Answers
Answered by
6
Answer:
ANSWER
ax
2
+bx+c=0
roots are
2a
−b+
b
2
−4ac
α=
2a
−b+
b
2
4ac
β=
2a
−b−
b
2
−4ax
r=
β
α
=(
−b+
b
2
−4ac
−b+
b
2
4ac
)
=
−(b+
b
2
−4ac
)
b−
b
2
−4ac
×
b−
b
2
−4ac
b−
b
2
−4ac
=
b−b
2
+4ac
(b−
b
2
−4ac
)
2
=
4ac
b
2
+b
2
−4ac−2b
b
2
−4ac
=
4ac
2b
2
−2b
b
2
−4ac
−4ac
Attachments:
Similar questions