Question

Show that the ratio series
connection to the parallel connection of 'n' nos. of resistance is of value 'R' ohm is n2:1?


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Answer 1

Answer:

First of all, consider a circuit where "n" resistors are connected in series.

In that case, the net resistance is

= R+R+R+....... n times

= nR

Now consider a circuit where "n" resistors are connected in parallel with one another.

In that case the resistance is given by

1/R eq.= 1/R + 1/R + 1/R +........ n times

R eq. = R/n.

Now the required ratio of series to parallel combinations

= (nR)/ (R/n)

= n^2 : 1

Hence proved.

Answer 2

Answer:

may ot help you

Explanation:

refers to the attachment