show that the relation R={(a,b):a-b)= even integer and a,b€I}in the set I integers is an equivalence relation.
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(i) Since a−a=0 and 0 is an even integer
(a,a)∈R
∴ R is reflexive.
(ii) If (a−b) is even, then (b−a) is also even. then, if (a−b)∈R,(b,a)∈R
∴ The relation is symmetric.
(iii) If (a,b)∈R,(b,c)∈R, then (a−b) is even, (b−c) is even, then $$(a-b
+b-c)=a-c$$ is even.
∴ If (a,b)∈R,(b,c)∈R implies (a,c)∈R
∴ R is transitive.
Since R is reflexive, symmetric and transitive, it is an equivalence relation.
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