Show that the right circular cone of least curved surface and given volume has an altitude equal to √2 time the radius of the base.
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Show that the right circular cone of least curved surface and given volume has an altitude equal to 2 times the radius of the base. dr2d2S=12π2r2+r454V2>0 for all values of V and r. Hence, for the least surface area of a cone and given volume, altitude is equal to 2 times the radius of the base.
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Let ABC be right-circular cone having radius ‘r’ and height ‘h’. If V and S are its volume and surface area (curved) respectively, then
i.e., For least curved surface, altitude is equal to √2 times the radius of the base.
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