Question

Show that the roots of the equation
(p-q)x2+(q-r)x+(r-p)=0 are equal if 2p=r+s

Answer 1

Answer:

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Step-by-step explanation:

if the roots of the quadratic equation: p(q-r)x^2+q(r-p)x+r(p-q)=0 are equal, show that:1/p + 1/r = 2/q