Show that the roots of the equation
x2 + ax – b2=0 are real for all values of a and b.
Answers
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Step-by-step explanation:
centre of cirlce (
2
α+β
,
2
γ+δ
)→(−a,−p)
Radius of circle =
2
1
(α−β)
2
+(γ−δ)
2
=
2
1
(α+β)
2
−4αβ+(γ+δ)
2
−4γδ
=
2
1
4a
2
−4b
2
+4p
2
−4q
2
=
a
2
−b
2
+p
2
−q
2
Equation
(x+a)
2
+(y+p)
2
=a
2
−b
2
+p
2
−q
2
x
2
+y
2
+2ax+2py+b
2
+q
2
=0
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