Show that the sequence 9,12,15,18.....is an AP .find its 15th term and general term
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Answered by
4
Answer:
d=12-9=3
a=9
15th term =a+14d
9+14(3)
=9+42
=51
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Answered by
1
D1 = 12-9=3
D2 = 15-12= 3
Since D1 = D2 the following sequence is AP
In this AP A= 9 ,D=3 (1)
General form of 15th term of AP is a+14d
Putting value of (1) in this equation
15th term =(9)+ 14*(3)
15th term = 9+ 42
15th term = 51
Hope you understood
D2 = 15-12= 3
Since D1 = D2 the following sequence is AP
In this AP A= 9 ,D=3 (1)
General form of 15th term of AP is a+14d
Putting value of (1) in this equation
15th term =(9)+ 14*(3)
15th term = 9+ 42
15th term = 51
Hope you understood
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