Question

Show that the sequence 9,12,15,18....... Is an AP. Find its 16th term and the general term​

Answer 1

genarel term is

dn+f-d

=4n+9-4

= 4n+5

Step-by-step explanation:

16nth term

=4×16+5

=69

Answer 2

Answer:

a16 = 54.

General term (an) = 6+ 3n.

Step-by-step explanation:

The sequence is an AP because the common difference (d) is equal between two terms:-

a2-a1 = 12-9 = 3 = a3-a2 = a4-a3.

since, an= a+(n-1)d

so, a16 = 9+(16-1)3 = 9+ 45 = 54.

Therefore, a16 = 54.

Now, general term an:-

an = 9+ (n-1)3

= 9+ 3n-3

= 6+ 3n.

Therefore, general term (an) = 6 + 3n.