Show that the sequence defined by
an = 2n^2+n+1 is not in an A.P
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Step-by-step explanation:
A_n = 2n² + n + 1
Putting n=1,
A_1 = 2 × 1² + 1 + 1= 4
Putting n=2,
A_2 = 2 × 2² + 2 + 1 = 11
Putting n=3,
A_3 = 2 × 3² + 3 + 1 = 22
Common difference of A_2 &A_3 is ( A_3-A_2) = 22 - 11 = 11
Common difference of A_1 & A_2 is ( A_2 - A_1) = 11 - 4 = 7
Clearly, we see that, common difference are not same, so, given sequence A_n is not in an A.P.
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