Show that the sequence defined by is not an A.P.,
Answers
Answered by
4
Answer:
The given sequence is not an A.P.
Step-by-step explanation:
Given :
3n² - 5 …………(1)
On putting n = 1 in eq 1,
a1 = 3(1)² – 5
a1 = 3 - 5
a1 = -2
On putting n = 2 in eq 1 ,
a2 = 3(2)² – 5
a2 = 3 × 4 - 5
a2 = 12 – 5
a2 = 7
On putting n = 3 in eq,
a3 = 3(3)² – 5
a3 = 3 × 9 - 5
a3 = 27 - 5
a3 = 22
Common difference, d1 = a2 – a1
d1= 7 – (-2)
d1 = 7 +2
d1 = 9
Common difference, d2 = a3 – a2
d2 = 22 – 7
d2 = 15
Since, Common difference d1 & d2 are not equal i.e d1 ≠ d2 .
Hence, the given sequence is not an A.P.
HOPE THIS ANSWER WILL HELP YOU...
Answered by
2
Answer:
Step-by-step explanation:
When n = 1
3*1 - 5 = -2
when n = 2
3*4-5= 7
when n = 3
3*9-5 = 22
since the difference between the terms r not equal
hence they r not in AP
Anonymous:
sad dp
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