Show that the sequence defined by is an A.P., find its common difference
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Answer:
Common difference = 5 and the given sequence is an A.P.
Step-by-step explanation:
Given :
an = 5n - 7 ………………(1)
On putting n = 1 in eq 1,
a1= 5(1) – 7
a1 = 5 - 7
a1 = -2
On putting n = 2 in eq 1,
a2 = 5(2) – 7
a2 = 10 - 7
a2 = 10 – 7
a2 = 3
On putting n = 3 in eq 1,
a3 = 5(3) – 7
a3 = 15 - 7
a3 = 8
Common difference, d1= a2 – a1
d1= 3 – (-2)
d1 = 3 +2
d1 = 5
Common difference, d2= a3 – a2
d2 = 8 – 3
d2 = 5
Since, Common difference d1 & d2 are equal i.e d1 = d2 = 5
Hence, the given sequence is an A.P.
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