Question

show that the sequence defined by tn=4n+7 is an ap. pls answer asap

Answer 1

t1=4*1+7=4+7=11
t2=4*2+7=8+7=15
t3=4*3+7=12+7=19
Now, t2-t1=15-11=4
t3-t2=19-15=4
therefore, common difference is same.
hence, it is in A.P.

Answer 2

Answer:

T1=4 x 1+7=4+7=11

T2=4 x 2+7=8+7=15

T3=4 x 3+7=12+7=19

Now, T2-T1=15-11=4

T3-T2=19-15=4

therefore, common difference is same.

hence, it is in AP.

hope it helps...