Question

Show that the sq. of an odd +ve integer is of the form 8m+1.

Answer 1

Answer:

Any positive odd integer is of the form 2q+1, where q is a whole number..

Therefore, (2q+1)^2 = 4q^2+4q+1 = 4q(q+1)+1, -----(1)

q(q+1) is either 0 or even. So, it is 2m, where m is a whole number.

Therefore, (2q+1)^2= 4.2m+1 =8m+1. (From eq. 1)

Hope it helps you.✌✌

Answer 2

here is your answer

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