Question

Show that the square of an odd integer is of the form 4q+1 for the some integer q​

Answer 1

Answer:

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Step-by-step explanation:

Let a be any odd integer and b = 4. Then, by Euclid's algorithm, a = 4m + r for some integer m ≥ 0 and r = 0,1,2,3 because 0 ≤ r < 4. ... = 4q + 1, where q is some integer. Hence, The square of any odd integer is of the form 4q + 1, for some integer q.