Question

Show that the square of an odd positive
integer can be of the of form 6q+1 as 6q+3
for some integer q​

Answer 1

Answer:

Let b=6

therefore , a can be equal to

6q , 6q+1, 6q+2, 6q+3 , 6q+4, 6q +5

odd nos. :-6q+1, 6q+3

let, (6m+1)^2=36m^2+1+12m

(where,6m +1is a odd positive no. )

=6(6m^2+2m) +1

=6q+1 where,q=6m^2+2m

(6m+3)^2=36m^2+9+36m

=36m^2+36m+6+3

=6(6m^2+6m+1)+3

=6q+3 where,q =6m^2+6m+1