Question

show that the square of any odd integer is of form 4q+1 for some integer q​

Answer 1

Answer:

Step-by-step explanation:

any positive odd integer of the form 2m +1 , 2m +3, 2m+5

let x be any odd integer

then

x = 2m + 1

now we shall

on squaring both sides we get

x² = (2m +1)²

x² = 4m²+4m+1

x²= 4(m²+m) + 1.

we know  (m²+m) = q

x² = 4q + 1.

done

Answer 2

hope the answer helps u