Question

Show that the square of any odd positive integer is of the form 6q+1 or 6q+3 for some integer q

Answer 1

Answer:

here we should apply bq+r=0

• where r greater or equal to q greater than r
• so r =1,and b=6
• we should find q
• so 1^3 =1 we can put this in q place because it is also odd and the value of 1^3 is also 1 where 2^3 = 8 so
• 6(1^3)+1

1 cube is the value can exist here in q place