show that the square of any positive integer is either of the form 3m or 3m + 1 for some integer m.
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Answered by
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Let a be any positive integer.
a=bm+r
a=3m+r as b=3
0≤r<3
The possible values of r are 0,1 and 2
a=1,2,3,4.....
Square of any positive integer:-
(1)²=1=3(0)+1 (r=1)
(2)²=4=3(1)+1 (r=1)
(3)²=9=3(3)+0 (r=0)
(4)²=16=3(5)+1 (r=1)
Therefore,square of any positive integer is of the form 3m or 3m+1.
Hence proved,
Hope it helps
a=bm+r
a=3m+r as b=3
0≤r<3
The possible values of r are 0,1 and 2
a=1,2,3,4.....
Square of any positive integer:-
(1)²=1=3(0)+1 (r=1)
(2)²=4=3(1)+1 (r=1)
(3)²=9=3(3)+0 (r=0)
(4)²=16=3(5)+1 (r=1)
Therefore,square of any positive integer is of the form 3m or 3m+1.
Hence proved,
Hope it helps
Answered by
0
The question is same you can put 3m +1
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