Math, asked by mohit5084, 10 months ago

Show that the square of any positive odd integer is of the form 8k +1, for 6 respectively,​

Answers

Answered by NehaNair
0

Answer:

Step-by-step explanation:

= 8( 8m²+ 14m + 6 ) + 1 . = 8q + 1 . [ Where q = 8m² + 14m + 6 ] . Hence, the square of any odd positive integer is of the form 8q + 1 .

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