Question

show that the square of the positive integer q cannot be the form of 6q + 2 or6q + 5​

Answer 1

Step-by-step explanation:

Let a be the positive integer

and b = 6.

Then,

by Euclid's algorithm,

a = 6q + r for some integer q ≥ 0

and r = 0, 1, 2, 3, 4, 5 because 0 ≤ r < 5.

So, a = 6q or 6q + 1 or 6q + 2 or 6q + 3 or 6q + 4 or 6q + 5

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Answer 2

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