Question

show that the straight lines x+2y+1=0 and 2x-y+5=0 are perpendicular to each other​

Answer 1

Step-by-step explanation:

ax+by+c=0

slope(m) = -a/b

x+2y+1=0

m1= -1/2

2x-y+5=0

m2=2

Hence

m1. m2=-1

Hence the straight lines are perpendicular

Answer 2

Answer:

Slope of the straight line x+2y+1=0 is m

1

=−

coefficientofy

coefficientofx

=−

2

1

\

Slope of the straight line 2x−y+5=0 is m

2

=−

coefficientofy

coefficientofx

=−

−1

−2

=2

Product of the slopes m

1

m

2

=−

2

1

×2=−1

∴ The two straight lines are perpendicular.