Question

Show that the straight lines x-2y+3=0 and 6x+3y+8=0 are perpendicular.
11
Find​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

the equation is in the form ax+by+c=0

we know

for two lines to be perpendicular,

a1*a2 + b1*b2=0

(1*6)+(-2)*(3) = 0

6-6=0

0=0

lhs =rhs

hence proved