Question

show that the sum and products of a quadratic equation ax^2+bx+c=0 are -b/a,c/a respectively......​
plss answer correctly

Answer 1

Answer:

Step-by-step explanation:

Considering quadratic equation

ax²+bx+c = 0

We know the roots can be expressed as

x = (-b±√b²-4ac) / 2a

Assuming roots to be A and B

A = (-b+√b²-4ac) / 2a

B = (-b-√b²-4ac) / 2a

Therefore A + B ==>

(-b+√b²-4ac) + (-b-√b²-4ac) /4a

= -b-b / 4a

= -2b / 4a

==> -b/a. .......(To be found)

Now,

A.B ==>

(-b+√b²-4ac) (-b-√b²-4ac) / 2a× 2a

==>. (-b)² - (√b²-4ac)² / 4a²

..[(a+b)(a-b)= a²-b²]

==> b² - (b²- 4ac) / 4a²

==> 4ac / 4a²

==> c/a

Hope it helps you buddy, if you think I was right surely mark it as BRAINLIEST.