Question

show that the sum of 3different binary number of 4 digits which contains having zero at different places is 38.​

Answer 1

Answer:

Formul

n+ n/2 (n is even)

n-3n-1 (nis odd)

Examples

Using the rule above and starting with 12, the sequence will be

12-6-3-10-5-16¬8-4-2-1

Ifn=19 the sequence will be

19-58-29-88-44-22-11-34-17-52-26-13-40-20-10-5-16

-8-4-2-1

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Step-by-step explanation:

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Answer 2

$3 \: different \: binary \: digits \: number \: of \: 4 \: digits \: are \: as \: follows$

$= \: 0009 + 0009 + 0010 + 0010$

$= \: 0018 + 0020$

$= 38$