Show that the sum of any 2 medians of a triangle is greater than the third side
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There is a triangle ABC.
Extend BA to point D, so DA = CA
Join CD Angle ADC = ACD
Angle BCD > ACD,
so angle BCD > ADC (or BDC) So in triangle DCB,
line DB (or DA + AB) > BC But line DA = AC, so
lines AC + AB > BC
Extend BA to point D, so DA = CA
Join CD Angle ADC = ACD
Angle BCD > ACD,
so angle BCD > ADC (or BDC) So in triangle DCB,
line DB (or DA + AB) > BC But line DA = AC, so
lines AC + AB > BC
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