show that the sum of exterior angle of trangle is 360.
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Theorem: If any side of a triangle is extended, then the exterior angle so formed is the sum of the two opposite interior angles of the triangle.
Exterior Angle Property of a Triangle
In the given figure, the side BC of ∆ABC is extended. The exterior angle ∠ACD so formed is the sum of measures of ∠ABC and ∠CAB.
Proof: From figure 3, ∠ACB and ∠ACD forms a linear pair since they represent the adjacent angles on a straight line.
Thus, ∠ACB + ∠ACD = 180° ……….(2)
Also, from the angle sum property it follows that:
∠ACB + ∠BAC + ∠CBA = 180° ……….(3)
From equation (2) and (3) it follows that:
∠ACD = ∠BAC + ∠CBA
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SALUT AMIS!!
We know that,
Exterior angle + adjacent interior angle = 180
And if the sides are takes as n then,
Sum of all interior angles + Sum of all exterior angles = n × 180
Sum of all exterior angles =n × 180 - Sum of all interior angles.
Sum of all exterior angles = n × 180 -(n -2)× 180
180 n - 180 n + 360
= 360
Hence proved that sum of all exterior angles is 360
We know that,
Exterior angle + adjacent interior angle = 180
And if the sides are takes as n then,
Sum of all interior angles + Sum of all exterior angles = n × 180
Sum of all exterior angles =n × 180 - Sum of all interior angles.
Sum of all exterior angles = n × 180 -(n -2)× 180
180 n - 180 n + 360
= 360
Hence proved that sum of all exterior angles is 360
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