Show that the sum of first 20 even natural numbers is 21/20 times the sum of first 20 odd natural numbers.
Answers
Answered by
16
sum of first 20 even terms=2×20×21/2=420=2(1+2+3+4+......+20)
sum of first 20 odd terms=(40×41/2)-(2×20×21/2)=820-420=400
hece ans=420/400=21/20
sum of first 20 odd terms=(40×41/2)-(2×20×21/2)=820-420=400
hece ans=420/400=21/20
Answered by
6
Muther F.k.r your answer is wrong Please check this
Attachments:
Similar questions