Question

Show that the sum of roots of quadratic equation -x+ 3x - 3 =0​

Answer 1

Step-by-step explanation:

-x+3x-3=0 ,

2x-3=0 ,2x=3 ,x=3/2

Answer 2

SOLUTION

TO PROVE

Show that the sum of roots of quadratic equation

$\sf{ - {x}^{2} + 3x - 3 = 0}$

CONCEPT TO BE IMPLEMENTED

If $\alpha \: \: and \: \: \beta \:$are the zeroes of the quadratic equation $\sf{ a {x}^{2} + bx + c= 0}$

Then

$\displaystyle \: \alpha + \beta \: = - \frac{b}{a} \: \: and \: \: \: \alpha \beta \: = \frac{c}{a}$

EVALUATION

Here the given Quadratic equation is

$\sf{ - {x}^{2} + 3x - 3 = 0}$

$\sf{ \implies {x}^{2} - 3x + 3 = 0}$

Comparing the above equation with general quadratic equation $\sf{ a {x}^{2} + bx + c= 0}$ We get

a = 1 , b = - 3 , c = 3

Hence the required sum sum of roots of quadratic equation is

$\displaystyle \sf{ = - \frac{b}{a} }$

$\displaystyle \sf{ = - \frac{ - 3}{1} }$

$= 3$

Hence proved

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