Question

Show that the sum of roots of quadratic equation -x+3x-3=0 is 3​

Answer 1

Answer :

In -x^2 + 3x -3 = 0

a = -1

b = 3

c = -3

we know , sum of roots of quadratic equation = -b/a

hence , -b /a = -(3)/-1

= 3

therefore , it is shown that sum of roots is 3 .

Answer 2

Given : quadratic equation -x²+3x-3= 0  

To Find : Show that sum of the roots of quadratic equation is 3

Solution:

quadratic equation  ax² + bx + c = 0

sum of roots = -b/a

quadratic equation -x²+3x-3= 0  

=> a = - 1

  b = 3

c = 3

sum of roots = -b/a

= - 3/(-1)

= 3

hence sum of roots is 3

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