Question

show that the sum of roots of quadratic equation
-x²+3x-3=0 is 3.
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Answer 1

Answer:

So for the quadratic equation $a x^{2}+b x+c=0$

sum of roots, $\mathrm{s}=-\mathrm{b} / \mathrm{a}$

product of the roots, $\mathrm{p}=\mathrm{c} / \mathrm{a}$

so for the equation $\sqrt{3} x^{2}-\sqrt{6} x-3=0$

we have $a=\sqrt{3}, b=-\sqrt{6}, c=-3$

so $s=\sqrt{2}$

and $p=-\sqrt{3}$