Question

show that the sum of squares of sides of a rhombus is equal to the sum of squares of its diagonals​

Answer 1

Step-by-step explanation:

AB²+BC²+CD²DA²=AC²+DB²

AB²=BD²/4+AC²/4(P T)

SINCERELY

BC²=BD²/4+AC²/4

CD²=BD²/4+AC²/4

DA²=BD²/4+AC²/4

ADDING 4 eq

AB²+BC²+CD²+DA²=4(BD²+AC²)/4

AB²+BC²+CD²+DA²=BD²+AC²