Question

show that the surface of equal pressure is intersected orthogonally by the line of force.​

Answer 1

Answer:

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Answer 2

Answer:let the equi-pressure surface be

p=constant,

That, the direction cosine of the normal at point (x, y, z) on it are proportional to-

dp/dx, dp/dy, dp/dz

That is proportional to - rho X, rho Y, rho

That is proportional to- X, Y,

Hence the resultant force is along the normal. So that the line of force are normal to the equipressure surface.

Hence,the surface of equipressure are cut orthogonaly by the lines of force.

Step-by-step explanation: