Question

Show that the system of equation 4x+6y=7, 12x+8y=21, has infinitely many solutions

Answer 1

4x+6y=7

4x=7×6y

x=7×6y÷4

if y=1

x=7×6×2÷4

x=84÷4

x=21

you can put 3 values like this way

12x+8y=21

12x=21×8y

x=21×8y÷12

if y=2

x=21×8×2÷12

x=28

you can put 3 values like this way