Show that the tangent at any point 'A' on the
curve x=csecA, y=cTanA is ysinA= x-c cosA
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Answer:
Step-by-step explanation:
Given:
x=at2
y=at4
Then,
⇒t3=ax,t4=ay
⇒t=(ax)1/3t=(ay)1/4
⇒(ax)1/3=(ay)1/4
⇒(ax)31×124=(ay)41×12
⇒a4x4=a2y3
⇒y3=ax4 at P(h,k)
Also relation k3=ah4
Now by differentiation of after equation we get
3y2dxdy=a4x2
dxdy=3ay24x3
Now MT=dxdy=3ay24x3
Now we will find slope of tangent
MT/P(h,x)=3ax24h3
equation of tangent P(h,k)
y−k=3ak24h3(x−h)
⇒ Let y=0
Then, −k=3ak24h3(x−h)
⇒4h3−3ak3=x−h
Earlier we found that k3=ah4
Then ax3=h4
4h2−3h4=x−h
⇒4−3h+h=x
⇒x=4h
⇒hx=41
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