show that the total mechanical energy is conserved for a fool
feeling body
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Assume a body is at rest and is kept at a height of h .
Then the total mechanical energy of the body = Potential Energy of the body
= mgh
Now If the body is dropped from that height h, then
v² - u² = 2gh
As the body was initially at rest
v² = 2gh
gh = v²/2
Now lets put this in our potential energy
E = mgh
Putting gh =v²/2
E = mv²/2
Or (1/2) mv² which is equal to kinetic energy of the body with a mass m and velocity v so the mechanical energy is conserved.
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