Question

Show that the trajectory of a projectile is parabolic. ​

Answer 1

Answer:

Let a body is projected with speed um/s inclined θ with horizontal line.

Then, vertical component of u, u  

y

​  

=ucosθ

Horizontal component of u  

x

​  

=usinθ

acceleration on horizontal, ax=0

acceleration on vertical, ay=−g

Now, use formula  

X=u  

x

​  

t

X=ucosθ.t

t=X/ucosθ--------------------------(1)

Again, y=u  

y

​  

t+1/2a  

y

​  

t  

2

 

y=usinθt−1/2gt  

2

 

put equation  (1) here,

y=usinθ×x/ucosθ−1/2gt  

2

×x  

2

/u  

2

cos  

2

θ

=tanθx−1/2gx  

2

/u  

2

cos  

2

 

y=tanθ.x−1/2gx  

2

/u  

2

cos  

2

θ

this equation is similar to standard equation of parabola y=ax  

2

+bx+c her, a,band c are constant

So, A projectile motion is parabolic motion.

HOPE IT HELPS......!

Answer 2

Answer:

consider a particle thrown up at an angle qto the horizon Al with a velocity uthe ve