Show that the triangle formed by the points A(5,-1),B(-3,2) and C(1,6) is an isosceles triangle
Answers
Answered by
0
As we have to prove triangle ABC as isosceles triangle we need to find the lengths of sides.
X=5,Y=-1,x=-3,y=2
AB²=(X-x)²+(Y-y)²
=(5+3)²+(-1-2)²
=64+9
=73
AB=√73
Now X=-3,Y=2,x=1,y=6
BC²=(X-x)²+(Y-y)²
=(-3-1)²+(2-6)²
=16+16
=32
BC=√32
As AB≠BC
We will find AC
X=5,Y=-1,x=1,y=6
AC²=(5-1)²+(-1-6)²
AC²=16+49
AC=√65
Its not a isosceles triangle.
X=5,Y=-1,x=-3,y=2
AB²=(X-x)²+(Y-y)²
=(5+3)²+(-1-2)²
=64+9
=73
AB=√73
Now X=-3,Y=2,x=1,y=6
BC²=(X-x)²+(Y-y)²
=(-3-1)²+(2-6)²
=16+16
=32
BC=√32
As AB≠BC
We will find AC
X=5,Y=-1,x=1,y=6
AC²=(5-1)²+(-1-6)²
AC²=16+49
AC=√65
Its not a isosceles triangle.
Similar questions