Question

Show that the triangle whose vertices are A(4,-1), B(5,6) and C(1,3) is an isosceles right angled triangle ​

Answer 1

Answer:

BC=(x2−x1)2+(y2−y1 )2 =(6−10)2+(9−1)2 =(−4)2+82 =16+64 =80 =42×5 =45

We know that the distance between the two points (x1,y1) and (x2,y2) is d = √((x2-x1)^2+(y2-y1)^2) Let the given vertices be A = (8, - 4) , B = (9,5)