Question

show that the triplet (8,15,17) is pythagorean triplet
​

Answer 1

Answer:

Yes it is Pythagoras triplet

Step-by-step explanation:

Lets

a=8 b=15 c=17

$if \: a{2} + b {2} = c {2} \: then \\ this \: is \: pythagorous \: triplet$

$a { }^{2} + b {}^{2} = 64 + 225 \: = 289$

$c {}^{2} = 17 {}^{2} = 289$

Answer 2

Step-by-step explanation:

To show : The triplet (8,15,17) is Pythagorean triplet ?

Solution :

Pythagorean triplet defined as

$H^2=P^2+B^2$

where, H is the largest side

Here, H=17 , B=8 and P=15

Substitute in the formula,

17^2=15^2+8^2

289=225+64

289=289

LHS=RHS

It satisfy the Pythagorean triplet.

#Learn more

Show that the triplet (8,15,17) is Pythagorean triplet​

https://brainly.in/question/14016626