Question

.. Show that the two pair of lines 3x² + 8xy – 3y2 = 0 and
3x² +8xy - 3y2 + 2x – 4y -1=0 form a square​

Answer 1

Step-by-step explanation:

a) 21b–32+7b–20b21b–32+7b–20b

Answer: 21b–32+7b–20b21b–32+7b–20b

=21b+7b–20b–32=21b+7b–20b–32

=28b–20b–32=8b–32=28b–20b–32=8b–32

(b) –z2+13z2–5z+7z3–15z–z2+13z2–5z+7z3–15z

Answer: −z2+13z2–5z+7z3–15z-z2+13z2–5z+7z3–15z

=−z2+13z2–5z–15z+7z3=-z2+13z2–5z–15z+7z3

=12z2–20z+7z3=12z2–20z+7z3

(c) p–(p–q)–q–(q–p)p–(p–q)–q–(q–p)

Answer: p–(p–q)–q–(q–p)p–(p–q)–q–(q–p)

=p–p+q–q–q+p=p–p+q–q–q+p

=p–p+p+q–q–q=p–p+p+q–q–q

=p–q=p–q

(d) 3a–2b–ab–(a–b+ab)+3ab+b–a3a–2b–ab–(a–b+ab)+3ab+b–a

Answer: 3a–2b–ab–a+b–ab+3ab+b–a3a–2b–ab–a+b–ab+3ab+b–a

=3a

Answer 2

Step-by-step explanation:

hope u help u from above attachment