Question

Show that the two triangles given in the following figures are congruent please help
No wrong answers plss​

Answer 1

Step-by-step explanation:

here is your answer

hope it helps you

Answer 2

Recall the concepts of congruency and Pythagoras' theorem.

Given: Refer to image

Explanation:

In $\triangle ABC,$

Using Pythagoras' theorem,

$AC^2=AB^2+BC^2$

$\implies AC^2=12^2+16^2$

$\implies AC^2=144+256$

$\implies AC^2=400$

$\implies AC=\sqrt{400}$

$\implies AC=20 cm$

Length $CD=BD-BC$

$\implies CD=28-16$

$\implies CD=12cm$

In $\triangle CDE,$

$CE^2=CD^2+DE^2$

$\implies 20^2=12^2+DE^2$

$\implies 400=144+DE^2$

$\implies DE^2=256$

$\implies DE=\sqrt{256}$

$\implies DE=16cm$

Consider $\triangle ABC and \triangle CDE$

$AB=CD\\AC=CE\\BC=CE\\\angle ABC=\angle CDE=90^\circ$

$\triangle ABC \cong \triangle CDE$ (SSS congruency)