Question

show that the value of acceleration due to gravity decreases with altitude​

Answer 1

Answer:

For an object placed at a height h, the acceleration due to gravity is less as compared to that placed on the surface. As depth increases, the value of acceleration due to gravity (g) falls. The value of g is more at equator and less at poles.

For an object placed at a height h, the acceleration due to gravity is less as compared to that placed on the surface. As depth increases, the value of acceleration due to gravity (g) falls. The value of g is more at equator and less at poles.Values of g in SI: 9.806 ms-2

For an object placed at a height h, the acceleration due to gravity is less as compared to that placed on the surface. As depth increases, the value of acceleration due to gravity (g) falls. The value of g is more at equator and less at poles.Values of g in SI: 9.806 ms-2Formula: g = GM/r2

For an object placed at a height h, the acceleration due to gravity is less as compared to that placed on the surface. As depth increases, the value of acceleration due to gravity (g) falls. The value of g is more at equator and less at poles.Values of g in SI: 9.806 ms-2Formula: g = GM/r2Values of g in CGS: 980 cm s-2

For an object placed at a height h, the acceleration due to gravity is less as compared to that placed on the surface. As depth increases, the value of acceleration due to gravity (g) falls. The value of g is more at equator and less at poles.Values of g in SI: 9.806 ms-2Formula: g = GM/r2Values of g in CGS: 980 cm s-2Dimensional Formula: M0L1T-2