show that the value of g is equal to 9.8 metre per second square
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Answered by
31
g = MG/R^2,
where g – Acceleration due to gravity
M – mass of the Earth = 5.98 x 10^24 kg
G – Universal gravitational constant = 6.673 x 10^-11 Nm^2kg^-2
R – Radius of the Earth = 6.38 x 10^6 m
g = (5.98 x 10^24 x 6.673 x 10^-11) / (6.38 x 10^6)^2
g = (39.90454 x 10^13) / (40.7044 x 10^12)
g = 0.98034954 x 10
g = 9.8 m/s^2
where g – Acceleration due to gravity
M – mass of the Earth = 5.98 x 10^24 kg
G – Universal gravitational constant = 6.673 x 10^-11 Nm^2kg^-2
R – Radius of the Earth = 6.38 x 10^6 m
g = (5.98 x 10^24 x 6.673 x 10^-11) / (6.38 x 10^6)^2
g = (39.90454 x 10^13) / (40.7044 x 10^12)
g = 0.98034954 x 10
g = 9.8 m/s^2
Answered by
24
In a simple way the acceleration due to gravity of earth can be computed by
using g = GM/R^2
Where G is Universal Gravitational Constant ( 6.67 * 10^-11 N-m^2/Kg^2)
M is Mass of earth (6*10^24 Kg)
R is Radius of earth (6.4*10^6 m)
By plugging in the respective values in the above expression
g = (6.67 * 10^-11 N-m^2/Kg^2 ) x (6*10^24 Kg) / (6.4*10^6 m)^2
After simplification we will get g around 9.8 m/ s^2
thank you
hope it's help
using g = GM/R^2
Where G is Universal Gravitational Constant ( 6.67 * 10^-11 N-m^2/Kg^2)
M is Mass of earth (6*10^24 Kg)
R is Radius of earth (6.4*10^6 m)
By plugging in the respective values in the above expression
g = (6.67 * 10^-11 N-m^2/Kg^2 ) x (6*10^24 Kg) / (6.4*10^6 m)^2
After simplification we will get g around 9.8 m/ s^2
thank you
hope it's help
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