Show that the value of : x3 - 8x2 + 12x - 5 is zero, when x = 1
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Answered by
10
x3 - 8x2 + 12x - 5
= (1)³-8(1)²+12(1) -5
= 1-8+12-5
= 0
Answered by
5
Answer:
x^3 - 8x^2 +12 x - 5
putting x=1
L.H.S=
=(1)^3 -8(1)^2+12(1)-5
=1-8+12-5
=-7+7
= 0
hence proved
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