Question

show that the vector field F=2x (y^2+z^3) I +2x^2y j +3x^2z^2 k is conservative. What is its scalar potential and the work done is moving particle from (-1,2,-1) to (2,3,4).


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Answer 1

Answer:

86 and 45

is your correct answer

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Answer 2

Step-by-step explanation:

if F is conservation Curl f =0

the step by step has written in the image.

scalar potential = (x^2)(y^2)+ (x^2)(z^3) +c

c - constant

Work Done = 289

for moving particle from (-1,2,1) to (2,3,4)