Show that the weigh of an object on moon is 1/6 of that on earth.
Answers
Answer:
Explanation:
The equation for finding weight force is F = (G*M*m)/r^2. In this equation, G = 6.6E-11, M = planetary/moon mass, m = object mass, and r = distance to center of planet/moon.
If we keep the mass of the object at 10kg for both the moon and the Earth…
On Earth:
M = 5.972E24 kg
r (distance to center of Earth from surface) = 6.371E6 m
Weight force = ((6.67E-11)*(5.972E24)*10)/6.371E6^2 = 98.13 N
On the Moon:
M = 7.347E22 kg
r (distance to center of Moon from surface) = 1.738E6 m
Weight force = ((6.67E-11)*(7.34E22)*10)/1.738E6^2 = 16.21 N
Comparing the two weight forces:
16.21 N (Moon weight force) / 98.13
N (Earth weight force) = 0.16 = 1/6
Answer:
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Show that weight of an object on the moon is 1/6 of its weight on the earth. [Given : mass of earth = 5.98 x 1024 kg, mass of moon = 7.36 x 1022 kg, radius of earth = 6.37 x 106 m, radius of moon = 1.74 x 106 m]
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