Show that there are two angle of projection for which horizontal ranges are equal
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R = u^2 sin(2 theta) / g.
Put 90- theta in the eqn.
we get R' = u^2 sin( 180- 2 theta)/g .
As sin(180- theta)= sin(theta).
R'= R
So 2 angles are theta and 90- theta
Put 90- theta in the eqn.
we get R' = u^2 sin( 180- 2 theta)/g .
As sin(180- theta)= sin(theta).
R'= R
So 2 angles are theta and 90- theta
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