Show that there does exist a rational number t such that t^2 = 3.
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no there isn't a no......
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Answer to Question #3408 in Real Analysis for junel
Show that there does not exist a rational number t such t[sup]2[/sup] = 3. Then 3 divides by p2. either p, p + 1 or p + 2 is divisible by 3. Suppose that p + 1 = 3n for some n∈N.
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